Mole Fraction

Three statements are given about mole fraction (i) Mole fraction of a solute + mole fraction of solvent = 1 (ii) Equal weights of Helium and methane are present in a gaseous mixture. The mole fraction of He is 4/5 (iii) The mole fraction of water in the aqueous solution of NaOH is 0.8. The molality of the solution is nearly 14 moles kg^(-1)

For an equimolar ideal mixture of A and B with p_(A)^(0)ltp_(B)^(0) : x_(A)= mole fraction of A in solution x_(B)= mole fraction of B in solution y_(A)= mole fraction of A in vapour phase y_(B)= mole fraction of B in vapour phase solution

Assertion: The weight percentage of a compound A in a solution is given by % of A=("Mass A")/("Total mass of solution")xx100 Reason: The mole fraction of a component A is given by, Mole fraction of A =("No. of moles of A")/("Total no. of moles of all components")