REACTION WITH HYDROXYLAMINE~

Fractional Oxidation States|Classical Idea Of Redox Reaction|Oxidizing Agent|Reducing Agent|Types Of Redox Reaction|Chemical Combination Reactions|Decomposition Reactions|Displacement Reactions|Disproportionation Reactions|Comproportionation Reactions|OMR

The reactions of hydroxylamine with a symmetrical ketone (R_(2)C = O) froms only one oxmie. However two isomeric oximes may be formed when an aldehyde or non-symmetical ketone takes part in the reaction. Explain.

An organic compound (A) C_(6)H_(12)O reacts with hydroxylamine to give an oxime. It also reduces Tollen's reagent and undergoes cannizzaro's reaction. What is the structure of (A)? Write down the different reactions involved.

The product formed when hydroxylamine condenses with a carbonyl compound is called (A) Hydrazide (B) Oxime (C) Hydrazine (D) Hydrazone

A certain compound has a formula C_(3)H_(6)O . It combine with hydroxylamine to form two compounds which are geometrical isomers of each other. It is

(a). If both (A) and (R) are correct and (R) is the correct explanation for (A). (b). If both (A) and (R) are correct and (R) is the correct explanation for (A). (c). If (A) is correct and (R) is incorrect. (d). If (A) is incorrect and (R) is correct. ltbr. (e). If both (A) and (R) are incorrect. Q. Assertion (A): Hydroxylamine (NH_2OH) contains N, and hence gives prussian blue colour in lassaigne's test. Reason (R): Hydroxylamine does not contain C, so with Na metal. CN^(c-) ion is not formed.