Hoffmann Mustard Oil Reaction

Chloroform and ethanolic KOH is used as a reagent in the following reaction: (a) Hoffmann carbylamine reaction (b) Hoffmann degradation reaction (c) Reimer-Tiemann reaction (d) Hoffmann mustard oil reaction Code is:

Which of the following is Hofmann mustard oil reaction?

(a) Why is the secondary amine more basic than primary amine? (b) Explain Hoffman mustard oil reaction. (c) How is a primary amine distinguished from a secondary amine using a chemical test?

Amine not showing Hofmann's mustard oil reaction is

Of the following amines how many can be separately by Hofmann's mustard oil reaction?

Hofmann Mustard Oil Test|Hofmann's Methods|Diazonium Salts|Method Of Preparation Of Diazonium Salts|Chemcial Reactions Of Diazonium Salts|Gutterman Reaction|Summary

The product of mustard oil reaction is