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Molarity And Normality

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KMnO_(4) solution is to be standardised by titration against As_(2)O_(3) (s) . A 0.1097 g sample of As_(2)O_(3) requires 26.10 mL of the KMnO_(4) solution for its titration. What are the molarity and normality of the KMnO_(4) solution (Mol. Wt. of As=75)

In which of the following expression the concentration of the solution remains independent of temperature :- Molarity Normality Mole fraction Percentage strength (w/v)

Knowledge Check

  • Molarity , normality and molality of the solution containing 22% of Al_2(SO_4)_3{d=1.253g//mL} by weight are

    A
    `0.825 M, 48.3 N,0.825m`
    B
    `0.805 M, 4.83 N,0.825m`
    C
    `4.83M, M, 4.83 N,4.83m`
    D
    None
  • Molarity is

    A
    the number of moles of solute present in `1 dm^(3)` volume of solution
    B
    the number of moles of solute dissolved in 1 kg of solvent
    C
    the number of moles of solute dissoved in 1 kg of solution
    D
    the number of moles of solute dissolved in 100 `dm^(3)` volume of solution
  • A solution of Al_(2)(So_(4))_(3){d=1.253 gm//ml} contain 22% salt by weight. The molarity , normality and molality of the solution is

    A
    `0.825 M, 48.3 N, 0.805` m
    B
    `0.805 M,4.83 N,0.825` m
    C
    `4.83M,4.83 N, 4.83` m
    D
    None
  • Similar Questions

    Explore conceptually related problems

    "A commerically available sample of sulphuric acid is 15% "H_(2)SO_(4)" by mass" ("density "= 1.10 g mL^(-1)). Calculate : Molarity Normality Molality of solution.

    Molarity is

    Concentration and concentration terms|Molarity|Normality|Formality|Parts per million

    A commerically availabe sample of sulphuric acid is 15% H_(2)SO_(4) by weight (density = 1.10 g mL^(-1) ). Calculate (i) molarity (ii) normality and (iii) molality of the solution.

    KMnO_(4) solution is to be standaridised by titration against AsO_(3)(s) . A 0.1097g sample of As_(2)O_(3) requires 26.10mL of the solution for its titration. What are the molarity and normally of the KMnO_(4) solution?