`(cos^2x+cosx+2)/(cos^2x+cosx+1)` find range.

int (cosx-cos2x)/(1-cosx) dx

int (cosx-cos2x)/(1-cosx) dx

16 sin x cosx cos 2x cos 4x cos 8x in

Let f(x)=[(sin^2x,sinx,1),(sinx,1,sin^2x),(1,sin^2x,sinx)] and g(x)=[(cos^2x,cosx,1),(cosx,1,cos^2x),(1,cos^2x,cosx)]. If h(x)=Tr.(f(x)g(x)), then find the absolute value of the difference between maximum and minimum value of h(x). [Tr. (P) denotes the trace of Matrix P]

int(1-cosx)cos^(2)x dx=

The value of lim_(xrar2pi)(cos x-(cosx)^(cosx))/(1-cos x+ln(cosx)) is equal to

The value of lim_(xrar2pi)(cos x-(cosx)^(cosx))/(1-cos x+ln(cosx)) is equal to

Prove : int (cos x - cos 2x)/(1-cosx) dx = x + 2 sin x + c

Solve cosx+cos3x-2cos2x=0