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Each of A and B tosses two coins. What i...

Each of A and B tosses two coins. What is the probability that they get equal number of heads ?

A

`3/16`

B

`5/16`

C

`4/16`

D

`6/16`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability that A and B get an equal number of heads when each tosses two coins, we can follow these steps: ### Step 1: Determine the Sample Space When tossing two coins, the possible outcomes for each toss can be represented as: - HH (2 heads) - HT (1 head, 1 tail) - TH (1 head, 1 tail) - TT (0 heads) Thus, the sample space for tossing two coins is: \[ S = \{ HH, HT, TH, TT \} \] This gives us a total of 4 outcomes. ### Step 2: Calculate the Probability of Each Outcome The probabilities of getting 0, 1, or 2 heads when tossing two coins can be calculated as follows: - Probability of getting 0 heads (TT): \( P(0) = \frac{1}{4} \) - Probability of getting 1 head (HT or TH): \( P(1) = \frac{2}{4} = \frac{1}{2} \) - Probability of getting 2 heads (HH): \( P(2) = \frac{1}{4} \) ### Step 3: Identify Equal Outcomes for A and B Next, we need to find the scenarios where A and B have an equal number of heads. The possible cases are: 1. Both get 0 heads. 2. Both get 1 head. 3. Both get 2 heads. ### Step 4: Calculate the Probabilities for Each Case 1. **Both get 0 heads:** \[ P(A = 0 \text{ and } B = 0) = P(0) \times P(0) = \frac{1}{4} \times \frac{1}{4} = \frac{1}{16} \] 2. **Both get 1 head:** \[ P(A = 1 \text{ and } B = 1) = P(1) \times P(1) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} = \frac{4}{16} \] 3. **Both get 2 heads:** \[ P(A = 2 \text{ and } B = 2) = P(2) \times P(2) = \frac{1}{4} \times \frac{1}{4} = \frac{1}{16} \] ### Step 5: Sum the Probabilities Now, we sum the probabilities of the cases where A and B have equal heads: \[ P(\text{equal heads}) = P(A = 0 \text{ and } B = 0) + P(A = 1 \text{ and } B = 1) + P(A = 2 \text{ and } B = 2) \] \[ P(\text{equal heads}) = \frac{1}{16} + \frac{4}{16} + \frac{1}{16} = \frac{6}{16} = \frac{3}{8} \] ### Step 6: Final Probability Thus, the probability that A and B get an equal number of heads is: \[ \frac{3}{8} \]

To solve the problem of finding the probability that A and B get an equal number of heads when each tosses two coins, we can follow these steps: ### Step 1: Determine the Sample Space When tossing two coins, the possible outcomes for each toss can be represented as: - HH (2 heads) - HT (1 head, 1 tail) - TH (1 head, 1 tail) - TT (0 heads) ...
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