Given that `P(A) = 1//3, P(B) = 3//4` and `P(A uu B) = 11//12` then what is `P(B//A)` ?

Options

A. `1//6`
B. `4//9`
C. `1//2`
D. `1//3`

Answer

C

Explanation

We know `P(A uu B) = P(A) + P(B) - P(A nn B)`
`rArr P(A nn B) = 1/3 + 3/4 - 11/12 = 2/12 = 1/6`
Consider `P(B//A) = (P(A nn B))/(P(A)) = (1//6)/(1//3) = 1/2`