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Find the probability of 53 Sundays and 5...

Find the probability of 53 Sundays and 53 Mondays in a leap year.

A

`2//7`

B

`3//7`

C

`4//7`

D

`5//7`

Text Solution

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The correct Answer is:
B
A leap year has 366 days, in which 2 days may be any one of the following pairs.
(Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday).
`therefore` Required probability `= 2/7 + 2/7 - 1/7 = 3/7`
)By using `P(A uu B) = P(A) + P(B) - P(A nn B)`
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