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A husband and wife appear in an intervie...

A husband and wife appear in an interview for two vacancies in the same post. The probability of husband's selection is 1/5 and that of wife's selection is 1/3. What is the probability that only one of them will be selected ?

A

`1//5`

B

`2//5`

C

`3//5`

D

`4//5`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the probability that only one of the husband or wife is selected for the vacancies. Let's denote: - Event A: Husband is selected - Event B: Wife is selected Given: - Probability of husband being selected, P(A) = 1/5 - Probability of wife being selected, P(B) = 1/3 We need to find the probability that only one of them is selected. This can happen in two scenarios: 1. The husband is selected and the wife is not selected. 2. The wife is selected and the husband is not selected. ### Step 1: Calculate the probability that the husband is selected and the wife is not selected. The probability that the wife is not selected is given by: \[ P(B') = 1 - P(B) = 1 - \frac{1}{3} = \frac{2}{3} \] Now, the probability that the husband is selected and the wife is not selected is: \[ P(A \cap B') = P(A) \times P(B') = \frac{1}{5} \times \frac{2}{3} = \frac{2}{15} \] ### Step 2: Calculate the probability that the wife is selected and the husband is not selected. The probability that the husband is not selected is given by: \[ P(A') = 1 - P(A) = 1 - \frac{1}{5} = \frac{4}{5} \] Now, the probability that the wife is selected and the husband is not selected is: \[ P(A' \cap B) = P(A') \times P(B) = \frac{4}{5} \times \frac{1}{3} = \frac{4}{15} \] ### Step 3: Add the probabilities of the two scenarios. Now, we can find the total probability that only one of them is selected by adding the probabilities from Step 1 and Step 2: \[ P(\text{Only one selected}) = P(A \cap B') + P(A' \cap B) = \frac{2}{15} + \frac{4}{15} = \frac{6}{15} \] ### Step 4: Simplify the result. Finally, we simplify the fraction: \[ \frac{6}{15} = \frac{2}{5} \] Thus, the probability that only one of them will be selected is: \[ \boxed{\frac{2}{5}} \]

To solve the problem, we need to find the probability that only one of the husband or wife is selected for the vacancies. Let's denote: - Event A: Husband is selected - Event B: Wife is selected Given: - Probability of husband being selected, P(A) = 1/5 ...
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