An urn contains one black ball and one green ball. A second urn contains one white and one green ball. One ball is drawn at random from each urn.
What is the probability of getting at least one green ball?

Options

A. `1//2`
B. `1//3`
C. `2//3`
D. `3//4`

Answer

D

Explanation

`"Required prob"=(1G)_(1)xx(1G)_(II)=(1G)_(1)xx(IB)I+(1G)_(II)xx(1W)_(II)`
`=((1)/(2)xx(1)/(2))+((1)/(2)xx(1)/(2))+((1)/(2)xx(1)/(2))=(1)/(4)+(1)/(4)+(1)/(4)=(3)/(4)`