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A fair coin is tossed repeatedly. The pr...

A fair coin is tossed repeatedly. The probability of getting a result in fifth toss different from those obtained in the first four tosses is

A

`(1)/(2)`

B

`(1)/(32)`

C

`(31)/(32)`

D

`(1)/(16)`

Text Solution

Verified by Experts

The correct Answer is:
D

`P(HHHHT or "TTTTH"=P(HHHHT)+P("TTTTH")`
`=((1)/(2))^(5)+((1)/(2))^(5)=(1)/(16)`
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