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In a relay race there are five teams A. B, C. D and E. (a) What is the probability that A. B and C finish first, second and third, respectively. (b) What is the probability that A. B and C are first three to finish (in any order) (Assume t

A

`(1)/(2)`

B

`(1)/(12)`

C

`(1)/(60)`

D

`(1)/(120)`

Text Solution

Verified by Experts

The correct Answer is:
B
Probability of A=`(1)/(6)`
Probability of B=`(1)/(5)`
Probability of C=`(1)/(4)`
Hence, required probability =`(1)/(6)xx(1)/(5)xx(1)/(4)=(1)/(120)`
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