It has been found that if A and B play a game 12 times, A wins 6 times, B wins 4 times and they draw twice. A and B take part in a series of 3 games. The probability that they will win alternately is

Options

A. `5//12`
B. `5//36`
C. `19//27`
D. `5//27`

Answer

B

Explanation

`P(A)=(6)/(12)=(1)/(2), P(B)=(4)/(12)=(1)/(3)`
`"Req. probability"=(1)/(2),(1)/(3),(1)/(2)+(1)/(3).(1)/(2).(1)/(3)=(1)/(12)+(1)/(18)=(5)/(36)`