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Two cards drawn without replacement from a well shuffled pack of 52 cards. Find the probability that cards drawn are aces.

A

`(1)/(26)`

B

`(1)/(221)`

C

`(4)/(223)`

D

`(1)/(13)`

Text Solution

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The correct Answer is:
B

`P(A)=(.^(4)C_(1))/(.^(52)C_(1))=(4)/(52)=(1)/(13)`
`P(B//A)=(.^(3)C_(1))/(.^(51)C_(1))=(3)/(51)=(1)/(17)`
`therefore" Required probability"=(1)/(13)xx(1)/(17)=(1)/(221)`
`therefore` Option (b) is correct.
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