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Two events A and B are such that P(not B...

Two events A and B are such that P(not B )=0.8 `P(A cup B)=0.5 and P(A|B)=0.4`. Then P(A) is equal to

A

0.28

B

0.32

C

0.38

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
`therefore P(overset(_)B)=0.58 Rightarrow P(B)=0.2`
`P(A cup B)=P(B)xxP(A|B)=0.2xx0.4=0.08`
`therefore P(A cap B)=P(B)xxP(A|B)=0.2xx0.4=0.08`
`& P(A)=P(A cup B)-P(B)+P(A cap B)`
`P(A)=0.5-0.2+0.08=0.38`
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