A coin is tossed three times. The probability of getting head and tail alternately, is

Options

A. `(1)/(8)`
B. `(1)/(4)`
C. `(1)/(2)`
D. `(3)/(4)`

Answer

B

Explanation

Coin is tossed three times i.e. total outcomes `= 2^(3) = 8`
[(H, H, H), (H, H,T), (H, T, H), (H, T, T), (T, H, H), (T, H, T), (T, T, H). (T, T, T)]
Alternate head and tail are coming two times only.
Thus prob. of getting head and tail alternately `=(2)/(8) = (1)/(4)`