Home
Class 12
MATHS
A question is given to theree students...

A question is given to theree students A,B and C whose chances of solving it are `(1)/(2),(1)/(3)` and `(1)/(4)` respectively. What is the probaility that the question will be solved ?

A

`(1)/(24)`

B

`(1)/(4)`

C

`(3)/(4)`

D

`(23)/(24)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the probability that at least one of the students A, B, or C solves the question. We can use the complementary probability approach, which involves calculating the probability that none of the students solve the question and then subtracting that from 1. ### Step-by-Step Solution: 1. **Identify the probabilities of each student solving the question:** - Probability that A solves the question, \( P(A) = \frac{1}{2} \) - Probability that B solves the question, \( P(B) = \frac{1}{3} \) - Probability that C solves the question, \( P(C) = \frac{1}{4} \) 2. **Calculate the probabilities of each student not solving the question:** - Probability that A does not solve the question, \( P(A') = 1 - P(A) = 1 - \frac{1}{2} = \frac{1}{2} \) - Probability that B does not solve the question, \( P(B') = 1 - P(B) = 1 - \frac{1}{3} = \frac{2}{3} \) - Probability that C does not solve the question, \( P(C') = 1 - P(C) = 1 - \frac{1}{4} = \frac{3}{4} \) 3. **Calculate the probability that none of the students solve the question:** - Since the events are independent, the probability that none of them solve the question is given by: \[ P(A' \cap B' \cap C') = P(A') \times P(B') \times P(C') = \frac{1}{2} \times \frac{2}{3} \times \frac{3}{4} \] 4. **Perform the multiplication:** - Calculate: \[ P(A' \cap B' \cap C') = \frac{1}{2} \times \frac{2}{3} \times \frac{3}{4} = \frac{1 \cdot 2 \cdot 3}{2 \cdot 3 \cdot 4} = \frac{6}{24} = \frac{1}{4} \] 5. **Calculate the probability that at least one student solves the question:** - The probability that at least one student solves the question is: \[ P(\text{at least one solves}) = 1 - P(A' \cap B' \cap C') = 1 - \frac{1}{4} = \frac{3}{4} \] 6. **Final Result:** - The probability that the question will be solved is \( \frac{3}{4} \).

To solve the problem, we need to find the probability that at least one of the students A, B, or C solves the question. We can use the complementary probability approach, which involves calculating the probability that none of the students solve the question and then subtracting that from 1. ### Step-by-Step Solution: 1. **Identify the probabilities of each student solving the question:** - Probability that A solves the question, \( P(A) = \frac{1}{2} \) - Probability that B solves the question, \( P(B) = \frac{1}{3} \) - Probability that C solves the question, \( P(C) = \frac{1}{4} \) ...
Promotional Banner

Topper's Solved these Questions

  • POLYNOMIAL,QUADRATIC EQUATION & INEQUALITIES

    NDA PREVIOUS YEARS|Exercise Math|170 Videos
  • PROPERTIES OF TRIANGLE, INVERSE TRIGONOMETRIC FUNCTION

    NDA PREVIOUS YEARS|Exercise MCQ|103 Videos

Similar Questions

Explore conceptually related problems

A problem is given to three students A, B and C whose probabilities of solving the problem are (1)/(2),(3)/(4) and (1)/(4) respectively. What is the probability that the problem will be solved if they all slove the problem independently?

A problem in statistics is given to four students A, B, C and D. Their chances of solving it are (1)/(3), (1)/(4), (1)/(5) and (1)/(6) respectively. What is the probability that the problem will be solved?

A problem in probability was given to three CA students A,B and C whose chances of solving it are 1/3,1/5 and 1/2 respectively.What is the probability that the problem would be solved.

A problem of mathematics is given to three students A, B, and C, whose chances of solving it are 1/2, 1/3, 1/4 respectively. Then find the probability that the problem will be solved.

A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will not be solved?

A problem is given to 3 students A, B and C whose chances of solving it are (1)/(2),(1)/(3) and (1)/(4) are respectively. Then the probability of the problem being solved by exactly one of them, if all the three try independently, is

A problem on mathematics is given to three students A,B,C whose probabilities of solving it are a (1)/(3),(2)/(5) and (3)/(4) respectively.Find the probability that the problem is solved.

NDA PREVIOUS YEARS-PROBABILITY AND PROBABILIYT DISTRIBUTION-Multiple Choice Question
  1. Let the random variable X follow B (6,p). If 16 P(X = 4) = P(X= 2), ...

    Text Solution

    |

  2. A committee of two persons is selected from two men and two women. The...

    Text Solution

    |

  3. A question is given to theree students A,B and C whose chances of s...

    Text Solution

    |

  4. For two dependent events A and B it is given that P(A) = 0.2 and P(B...

    Text Solution

    |

  5. A point is selected at random from the interior of a circle. The proba...

    Text Solution

    |

  6. A card is darw from a well - shuffled ordinary deck of 52 cards. What...

    Text Solution

    |

  7. Consider the followin Statements: 1. Two events are mutually exculs...

    Text Solution

    |

  8. If two fair dice are thrown, then what is the probability that the sum...

    Text Solution

    |

  9. Let A and B are two mutually exclusive events with P(A)= (1)/(3) P(B) ...

    Text Solution

    |

  10. The mean and standard deviation of a binomial distribution are 12 and ...

    Text Solution

    |

  11. A committee of two persons is selected from two men and two women. The...

    Text Solution

    |

  12. Let a die be loaded in such a way that even faces are twice likely to ...

    Text Solution

    |

  13. Let the sample space consist of non-negative integers up to 50, X deno...

    Text Solution

    |

  14. For two events A and B, let P(A) = (1)/(2) , P(A uuB) = (2)/(3) and P...

    Text Solution

    |

  15. Let A and B be tow events with P(A) = (1)/(3), P(B) = (1)/(6) and ...

    Text Solution

    |

  16. In a binomail distribution , then mean is (2)/(3) and the variance is...

    Text Solution

    |

  17. The probability that a ship safely reaches a port is (1)/(3). The prob...

    Text Solution

    |

  18. What is the probability that at least two persons out of a group of th...

    Text Solution

    |

  19. If P(B)=3/4, P(AnnBnnbarC)=1/3 and P(barAnnBbarC)=1/3 then P(BnnC)=

    Text Solution

    |

  20. In a multiple-choice test, an examinee either knows the correct answer...

    Text Solution

    |