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A point is selected at random from the interior of a circle. The probability that the point is closer to the centre than the boundary of the circle is

A

`(1)/(5)`

B

`(1)/(4)`

C

`(1)/(3)`

D

`(1)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Probability `= (pi((r)/(2))^(2))/(pir^(2))`
`(cancel(pi)((r^(2))/4))/(cancel(pi)r^(2))`
`=(r^(2))/(4r^(2)) = (1)/(4)`
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