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Let A and B are two mutually exclusive e...

Let A and B are two mutually exclusive events with `P(A)= (1)/(3) P(B) = (1)/(4)` What is the value of `P(bar(A) nn bar(B))` ?

A

`(1)/(6)`

B

`(1)/(4)`

C

`(1)/(3)`

D

`(5)/(12)`

Text Solution

Verified by Experts

The correct Answer is:
D
A & B are mutualy exclusive events i.e., `P( Ann B ) = 0` .
We know , `P(bar(A) nn bar(B)) = Pbar((A uu B))`
` = - P(AuuB)`
`= 1 - [P (A) +P(B) - P(A nnB)]`
` = 1-[(1)/(3) +(1)/(4) - 0]`
`= 1 -[(7)/(12)] = (5)/(12)`
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