A box has ten chits numbered 0, 1, 2, 3, .., 9. First, one chit is drawn at random and kept aside. From the remaining, a second chit is drawn at random. What is the probability that the second chit drawn is "9"?

Options

A. `(1)/(10)`
B. `(1)/(9)`
C. `(1)/(90)`
D. None of the above

Answer

C

Explanation

Given, 2P(A)=3.P(B)
`Rightarrow (2P(A))/(P(A cap B))=(3P(B))/(P(A cap B))`
`Rightarrow (P(A cap B))/(2.P(A))=(P(A cap B))/(3P(B))`
`=(1)/(2).P((B)/(A))=(1)/(3).P((A)/(B))`
`Rightarrow P((B)/(A)) lt P((A)/(B))`