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What is the length of the vector (1, 1) ...

What is the length of the vector (1, 1) ?

A

0

B

1

C

`sqrt(2)`

D

`1/2`

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The correct Answer is:
To find the length of the vector \( \mathbf{v} = (1, 1) \), we can use the formula for the length (or magnitude) of a vector in two dimensions. The formula is given by: \[ \text{Length} = \sqrt{x^2 + y^2} \] where \( x \) and \( y \) are the components of the vector. ### Step-by-step Solution: 1. **Identify the components of the vector**: The vector given is \( \mathbf{v} = (1, 1) \). Here, \( x = 1 \) and \( y = 1 \). 2. **Substitute the components into the formula**: We substitute \( x \) and \( y \) into the length formula: \[ \text{Length} = \sqrt{1^2 + 1^2} \] 3. **Calculate \( x^2 \) and \( y^2 \)**: \[ 1^2 = 1 \quad \text{and} \quad 1^2 = 1 \] 4. **Add the squares**: \[ 1 + 1 = 2 \] 5. **Take the square root**: \[ \text{Length} = \sqrt{2} \] Thus, the length of the vector \( (1, 1) \) is \( \sqrt{2} \). ### Final Answer: The length of the vector \( (1, 1) \) is \( \sqrt{2} \).

To find the length of the vector \( \mathbf{v} = (1, 1) \), we can use the formula for the length (or magnitude) of a vector in two dimensions. The formula is given by: \[ \text{Length} = \sqrt{x^2 + y^2} \] where \( x \) and \( y \) are the components of the vector. ...
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