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If veca, vecb, vecc are the position vec...

If `veca, vecb, vecc` are the position vectors of the vertices of an equilateral triangle whose orthocenter is at the origin, then

A

`vec(a)+vec(a)+vec(c)=vec(0)`

B

`vec(a)+vec(b)+vec(c)`= unit vector

C

`vec(a)+vec(b)=vec(c)`

D

`vec(a)=vec(b)+vec(c)`

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Verified by Experts

The correct Answer is:
A

Position vectors of vertices A, B andC are `vec(a), vec(b) and vec(c)`.

`:'` triangle is equilateral.
`:.` Centroid and orthocenter will coincide.
Centroid `-=` orthocenter position vector
`=(1)/(3) (vec(a)+vec(b)+vec(c))`
`:'` given in question orthocenter is at origin.
Hence `(1)/(3)(vec(a)++vec(b)+vec(c))=0`
`vec(a)+vec(b)+vec(c)=0`
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