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Which one of following is correct ? Th...

Which one of following is correct ?
The three planes `2x+3y-z-2=0, 3x+3y+z-4=0,x-y+2z-5=0` intersect

A

at a point

B

at two points

C

at three points

D

in a line

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The correct Answer is:
To determine whether the three given planes intersect and to find the nature of their intersection, we can follow these steps: ### Step 1: Write down the equations of the planes. The equations of the planes are: 1. \( 2x + 3y - z - 2 = 0 \) (Plane 1) 2. \( 3x + 3y + z - 4 = 0 \) (Plane 2) 3. \( x - y + 2z - 5 = 0 \) (Plane 3) ### Step 2: Convert the equations into a matrix form. We can represent the system of equations in matrix form \( AX = B \), where \( A \) is the coefficient matrix, \( X \) is the variable matrix, and \( B \) is the constant matrix. \[ A = \begin{bmatrix} 2 & 3 & -1 \\ 3 & 3 & 1 \\ 1 & -1 & 2 \end{bmatrix}, \quad X = \begin{bmatrix} x \\ y \\ z \end{bmatrix}, \quad B = \begin{bmatrix} 2 \\ 4 \\ 5 \end{bmatrix} \] ### Step 3: Calculate the determinant of the coefficient matrix \( A \). To check whether the planes intersect at a point, we need to calculate the determinant of matrix \( A \). \[ \text{det}(A) = \begin{vmatrix} 2 & 3 & -1 \\ 3 & 3 & 1 \\ 1 & -1 & 2 \end{vmatrix} \] Calculating the determinant using the rule of Sarrus or cofactor expansion: \[ = 2 \begin{vmatrix} 3 & 1 \\ -1 & 2 \end{vmatrix} - 3 \begin{vmatrix} 3 & 1 \\ 1 & 2 \end{vmatrix} - 1 \begin{vmatrix} 3 & 3 \\ 1 & -1 \end{vmatrix} \] Calculating the 2x2 determinants: 1. \( \begin{vmatrix} 3 & 1 \\ -1 & 2 \end{vmatrix} = (3)(2) - (1)(-1) = 6 + 1 = 7 \) 2. \( \begin{vmatrix} 3 & 1 \\ 1 & 2 \end{vmatrix} = (3)(2) - (1)(1) = 6 - 1 = 5 \) 3. \( \begin{vmatrix} 3 & 3 \\ 1 & -1 \end{vmatrix} = (3)(-1) - (3)(1) = -3 - 3 = -6 \) Now substituting back into the determinant calculation: \[ \text{det}(A) = 2(7) - 3(5) - 1(-6) = 14 - 15 + 6 = 5 \] ### Step 4: Analyze the determinant. Since \( \text{det}(A) \neq 0 \), the three planes intersect at a unique point. ### Conclusion: The three planes intersect at a single point, which means they do not intersect in a line. Therefore, the correct statement is that the three planes intersect at a point.

To determine whether the three given planes intersect and to find the nature of their intersection, we can follow these steps: ### Step 1: Write down the equations of the planes. The equations of the planes are: 1. \( 2x + 3y - z - 2 = 0 \) (Plane 1) 2. \( 3x + 3y + z - 4 = 0 \) (Plane 2) 3. \( x - y + 2z - 5 = 0 \) (Plane 3) ...
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