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The poins of extremum of phi(x)=int(1)^(...

The poins of extremum of `phi(x)=int_(1)^(x) e^(-t^(2)//2) (1-t^(2))dt` are

A

`x=1,-1`

B

`x=-1,2`

C

`x=2,1`

D

`x=-2,1`

Text Solution

Verified by Experts

The correct Answer is:
A
We have,
`phi(x)=underset(1)overset(x)inte^(-t^(2)//2) (1-t^(2))dt rArr phi'(x)=e^(-x^(2)//2)(1-x^(2))`
`:. phi' (x) =0 rArr x=+-1`
Hence, the points of extremum are `x=+-1`
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