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If f(x)= Min {|x-1|,|x|,|x+1|} "then" in...

If f(x)= Min `{|x-1|,|x|,|x+1|} "then" int_(-1)^(1)f(x)dx` eqals

A

1

B

2

C

0

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
D
The graph of f(x) is as shown in Fig. 10.
`underset(-1)overset(1)intf(x)dx=2underset(-1)overset(1)intf(x)dx=2((1)/(2)xx1xx(1)/(2))=(1)/(2)`
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