The value
`int^(2)_(-2) {p" In"((1+x)/(1-x))+q" In "((1-x)/(1+x))-2+r}dx` depends on the value of

Options

A. p
B. q
C. r
D. p and q

Answer

C

Explanation

`overset(2)underset(-2)int {p" In"((1+x)/(1-x))+q" In "((1-x)/(1+x))-2+r}dx`
`rArr I=poverset(2)underset(-2)int "In"((1+x)/(1-x))dx-2qoverset(2)underset(-2)int "In"((1-x)/(1+x))dx+overset(2)underset(-2)int' r dx`
`rArr I=pxx0-2qxx0+4r=4r[:'"In"((1+x)/(1-x))"and In"((1-x)/(1+x))"are odd functions"]`