If the focal distance of an end of the minor axis of an ellipse (referred to its axes as the axes of `xa n dy` , respectively) is `k` and the distance between its foci is `2h ,` them find its equation.

Options

A. `(x^(2))/(k^(2))+(y^(2))/(h^(2))=1`
B. `(x^(2))/(k^(2))+(y^(2))/(k^(2)-h^(2))=1`
C. `(x^(2))/(k^(2))+(y^(2))/(h^(2)-k^(2))=1`
D. `(x^(2))/(k^(2))+(y^(2))/(k^(2)+h^(2))=1`

Answer

B