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A(z(1)) and B(z(2)) are two fixed points...

`A(z_(1))` and `B(z_(2))` are two fixed points in the Argand plane and P(z) is variable point satisfying `|z-z_(1)|=k|z-z_(2)|`, where `k gt 0` and `k ne 1`. The locus of is

A

a circle

B

a parabola

C

an ellipse

D

a hyperbola

Text Solution

Verified by Experts

The correct Answer is:
D

We have,
`|z-z_(1)|=k|z-z_(2)|`
`rArr` PA=kPB
`rArr (PA)/(PB) = k rArr` Locus of P is a cycle.
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OBJECTIVE RD SHARMA-COMPLEX NUMBERS -Chapter Test
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  2. The locus of the center of a circle which touches the circles |z-z1|=a...

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  10. The value of the expression (1+1/omega)(1+1/omega^(2))+(2+1/omega)(2+...

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  12. The expression (1+i)^(n1)+(1+i^(3))^(n(2)) is real iff

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  13. |{:("6i " "-3i " "1" ),("4 " " 3i" " -1"),("20 " "3 " " i"):}|=x+iy th...

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  18. If az(1)+bz(2)+cz(3)=0 for complex numbers z(1),z(2),z(3) and real num...

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  19. If 2z1-3z2 + z3=0, then z1, z2 and z3 are represented by

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  20. Re((z+4)/(2z-1)) = 1/2, then z is represented by a point lying on

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  21. The vertices of a square are z1,z2,z3 and z4 taken in the anticlockwis...

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