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If (1+i)z=(1-i)barz, then z is equal to...

If `(1+i)z=(1-i)barz`, then z is equal to

A

`t(1-i), t in R`

B

`t(1+i),t in R`

C

`t/(1+i),t in R^(+)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
We have,
`(1+i)z=(1-i)barz`
`rArr (1+i)z=bar((1+i)z)`
`rArr z(1+i)=alpha`, where `alpha in R`
`rArr z=alpha/(1+i)`, Where `alpha in R`
`rArr z=t(1-i)`, where `t=alpha//2 in R`
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