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I f|z|=max{|z-1|,|z+1|}, then...

`I f|z|=max{|z-1|,|z+1|}`, then

A

`|z+barz|=1/2`

B

`z+barz=1`

C

`|z+barz|=1`

D

z-barz=5`

Text Solution

Verified by Experts

The correct Answer is:
C
If `|z|=|z-1|`, then
`|z|^(2)=|z-1|^(2)`
`zbarz=zbarz-z-barz+1 rArr z+barz=1 rArr |z+barz|=1`
At `z=|z+1|`, then
`|z|^(2)=|z+1|^(2)`
`rArr zbarz=zbarz+barz+z+1 rArr z+barz=-1 rArr |z+barz|=1`
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OBJECTIVE RD SHARMA-COMPLEX NUMBERS -Section I - Solved Mcqs
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