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If omega !=1 is the complex cube root o...

If `omega !=1` is the complex cube root of unity and matrix `H=[(omega,0), (0,omega)],` then `H^70` is equal to

A

`-H`

B

`H^(2)`

C

H

D

O

Text Solution

Verified by Experts

The correct Answer is:
C
We have, `H=omega[{:(1,0),(0,1):}]=omegaI_(2)`
`therefore H^(70)=omega^(70)(I_(2))^(70)=omegaI_(2)=H`.
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