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If z is a complex number such that |z|>=...

If `z` is a complex number such that `|z|>=2` then the minimum value of `|z+1/2|` is

A

is strictly greater than `5/2`

B

is strictly greater than `3/2` but less than `5/2`

C

is equal to `5/2`

D

lies in the interval (1,2)

Text Solution

Verified by Experts

The correct Answer is:
D

We observe that `S=|z:|z| ge 2)` is the set of all points lying on or outside the circle centred at the origin and radius 2 and `|z+1/2|=|z-(-1/2+0i)|` is the distance of any point in S from the point `(-1//2,0)`. It is evident from Fig. that AP is minimum when P coincides with B and in that case `AP=AB=3//2` which lies in the interval (1,2).
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