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If cosA+cosB+cosC=0,sinA + sinB + sinC=0...

If `cosA+cosB+cosC=0`,`sinA + sinB + sinC=0`and `A+B+C=180^0`, then the value of `cos3A + cos3B + cos3C` is

A

3

B

`-3`

C

`sqrt(3)`

D

0

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The correct Answer is:
b
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