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The centre of a square ABCD is at z0dot ...

The centre of a square ABCD is at `z_0dot` If `A` is `z_1` , then the centroid of the ABC is `2z_0-(z_1-z_0)` (b) `(z_0+i((z_1-z_0)/3)` `(z_0+i z_1)/3` (d) `2/3(z_1-z_0)`

A

`z_(1)(cospi+-isinpi)`

B

`z_(1)/3(cospi+-isinpi)`

C

`z_(1)(cosalpha+-isinpi/2)`

D

`z_(1)/3(cospi/2+-isinpi/2)`

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The correct Answer is:
d
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