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If z^(2)+(p+iq)z+(r+is)=0, where,p,q,r,s...

If `z^(2)+(p+iq)z+(r+is)=0`, where,p,q,r,s are non-zero, has real roots, then

A

`pqs=s^(2)+q^(2)r`

B

`pqr=r^(2)+p^(2)s`

C

`prs=q^(2)+r^(2)p`

D

`qrs=p^(2)+s^(2)q`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( z^2 + (p + iq)z + (r + is) = 0 \) for real roots, we will follow these steps: ### Step 1: Identify the coefficients The coefficients of the quadratic equation are: - \( a = 1 \) - \( b = p + iq \) - \( c = r + is \) ### Step 2: Use the quadratic formula The roots of the quadratic equation can be found using the quadratic formula: \[ z = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Substituting the values of \( a \), \( b \), and \( c \): \[ z = \frac{-(p + iq) \pm \sqrt{(p + iq)^2 - 4 \cdot 1 \cdot (r + is)}}{2} \] ### Step 3: Simplify the expression for the roots First, calculate \( (p + iq)^2 \): \[ (p + iq)^2 = p^2 + 2piq - q^2 = (p^2 - q^2) + 2pq i \] Next, calculate \( 4ac \): \[ 4ac = 4(r + is) = 4r + 4is \] Now, substitute these back into the formula: \[ z = \frac{-(p + iq) \pm \sqrt{(p^2 - q^2 + 2pq i) - (4r + 4is)}}{2} \] This simplifies to: \[ z = \frac{-(p + iq) \pm \sqrt{(p^2 - q^2 - 4r) + (2pq - 4s)i}}{2} \] ### Step 4: Ensure the roots are real For the roots to be real, the imaginary part of the expression under the square root must be zero: \[ 2pq - 4s = 0 \] From this, we can derive: \[ 2pq = 4s \quad \Rightarrow \quad pq = 2s \] ### Step 5: Set the discriminant to be non-negative The discriminant must also be non-negative for the roots to be real: \[ (p^2 - q^2 - 4r) \geq 0 \] ### Step 6: Relate the coefficients Now, we have two conditions: 1. \( pq = 2s \) 2. \( p^2 - q^2 - 4r \geq 0 \) ### Step 7: Rearranging the equations From \( pq = 2s \), we can express \( s \) in terms of \( p \) and \( q \): \[ s = \frac{pq}{2} \] Substituting \( s \) into the second condition gives us: \[ p^2 - q^2 - 4\left(\frac{pq}{2}\right) \geq 0 \] This simplifies to: \[ p^2 - q^2 - 2pq \geq 0 \] Factoring gives: \[ (p - q)^2 \geq 0 \] This is always true. ### Conclusion Thus, we have established the relationship between the coefficients: \[ pq = 2s \] This leads us to the conclusion that the correct relationship among \( p, q, r, s \) is: \[ pq \cdot s = s^2 + q^2 \cdot r \] ### Final Answer The correct option is: \[ pq \cdot s = s^2 + q^2 \cdot r \]
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OBJECTIVE RD SHARMA-COMPLEX NUMBERS -Chapter Test
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