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% hydrolysis of 0.1M CH(3)COONH(4), when...

`%` hydrolysis of 0.1M `CH_(3)COONH_(4),` when `K_(a)(CH_(3)COOH)=K_(b)(NH_(4)OH)=1.8xx10^(-5)` is:

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Calculate the percentage hydrolysis & the pH of 0.02M CH_(3)COONH_4 . K_(b)(NH_(3))-1.6xx10^(-5),K_(a)(CH_(3)COOH)=1.6xx10^(-5)

pH of a solution of 0.1 M [CH_3COONH_4(aq)] is [given: K_a(CH_3COOH) = K_b(NH_4OH) = 1.8 x 10^-5)]

Determine the pH of a buffer solution consisting of 0.01(M) CH_(3)COOH and 0.03(M)" "CH_(3)COONa. Given: K_(a)(CH_(3)COOH)=1.8xx10^(-5) .

What is the concentration of CH_(3)COOH(aq.) in a solution prepared by dissolving 0.01 mole of NH_(4)^(+)CH_(3)COO^(-) in 1 L H_(2)O ? [K_(a) (CH_(3)COOH))=1.8xx10^(-5)),K_(b) (NH_(4)OH)=1.8xx10^(-5))]

Both conc. Being 1 M, the factor by which the percent hydrolysis of CH_3COO^- is greater in CH_3COONH_4 than in CH_3COONa is : [K_a(CH_3COOH)=K_b(NH_4OH)=1.8xx10^(-5)]

Carefully observe the given figure and using data provided find the EMF of shown Galvenic cell in volt: Solution A is 0.1M each in NH_(4)OH and NH_(4)CI and solution B is 0.1M each in CH_(3)COOH and CH_(3)COONa^(+) . [Given: K_(a)(CH_(3)COOH) = 10^(-5), K_(b) (NH_(4)OH) = 10^(-5) and (2.303RT)/(F) = 0.06 volt]

Carefully observe the given figure and using data provided find the EMF of shown Galvenic cell in volt: Solution A is 0.1M each in NH_(4)OH and NH_(4)CI and solution B is 0.1M each in CH_(3)COOH and CH_(3)COONa^(+) . [Given: K_(a)(CH_(3)COOH) = 10^(-5), K_(b) (NH_(4)OH) = 10^(-5) and (2.303RT)/(F) = 0.06 volt]