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[" 8.A simple pendulum has a time period...

[" 8.A simple pendulum has a time period "],[T_(1)" .When its point of suspension is "],[" moved vertically upwards according "],[" as "y=kt^(2)," where "y" is vertical distance "],[" covered and "k=1ms^(2)" ,its time period "],[" becomes "T_(2)" .Then,"(T_(1)^(2))/(T_(2)^(2))" is "(g=10ms^(-2))],[[" (IIT "2005)," b) "(11)/(10)],[" (C) "(6)/(5)," d) "(5)/(4)]]

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A simple pendulum has a time period T_(1) . When its point of suspension is moved vertically upwards according as y=kt^(2) , where y is vertical covered and k=1 ms^(-2) , its time period becomes T_(2) then (T_(1)^(2))/(T_(2)^(2)) is (g =10 ms^(-2))

A simple pendulum has time period T_(1) . The point of suspension is now moved upward according to the relation y= kt^(2)(k=1 ms^(-2)) where y is the vertical diplacement. The time period now becomes T_(2) . What is the ration (T_(1)^(2))/(T_(2)^(2)) ? Given g=10 ms^(-2)