In the figure shown `upsilon=2m//s` `omega=5rad//s` and `CP=1m`
In terms of `hati` and `hatj` find linear velocity of particle P.

In the shown figure, a=2m//s^(2),omega=(2t)rods^(-1) and CP=1m In terms of hati and hatj , find linear acceleration of the particle at P at P at t=1 s

In the shown figure, a=2m//s^(2),omega=(2t)rods^(-1) and CP=1m In terms of hati and hatj , find linear acceleration of the particle at P at P at t=1 s

In the figure shown omega=(v)/(2R) in terms of hati and hatj find linear velocities of particles M, N, R and S.

In the figure shown omega = v/2R in terms of i and j find the linear velocities of particles M,N,R and S .

A circular disc is rotating with an angular speed (in radian per sec) omega=2t^(2) given, CP=2m In terms of hati,hatj and hatk at t=1s find, (a). omega (b). alpha (c). linear velocity of the particle lying at P (d). linear acceleration of the particle lying P

A circular disc is rotating with an angular speed (in radian per sec) omega=2t^(2) given, CP=2m In terms of hati,hatj and hatk at t=1s find, (a). omega (b). alpha (c). linear velocity of the particle lying at P (d). linear acceleration of the particle lying P

If angular velocity of a particle having position vector vec r = (2hati - 2hatj + 2hatk)m about the origin is vec w = (2hati - 2hatj - hatk)rad/s then magnitude of linear velocity of the particle will be

If angular velocity of a particle having position vector vec r = (2hati - 2hatj + 2hatk)m about the origin is vec w = (2hati - 2hatj - hatk)rad/s then magnitude of linear velocity of the particle will be

If angular velocity of a point object is vecomega=(hati+hat2j-hatk) rad/s and its position vector vecr=(hati+hatj-5hatk) m then linear velocity of the object will be

If angular velocity of a point object is vecomega=(hati+hat2j-hatk) rad/s and its position vector vecr=(hati+hatj-5hatk) m then linear velocity of the object will be