In a `triangleABC`, if `|[1,1,1][1+sinA,1+sinB,1+sinC],[sinA+sin^2A,sinB+sin^2B,sinC+sin^2C]|=0`, then prove that `triangleABC` is an isosceles triangle.

In a Delta ABC |[1,1,1],[1+sinA,1+sinB,1+sinC][sinA+sin^2A,sinB+sin^2B,sinC+sin^2C]|=0

If A,B and C are the angles of a triangle and |{:(1,1,1),(1+sinA,1+sinB,1+sinC),(sinA+sin^(2)A,sinB+sin^(2)B,sinC+sin^(2)C):}| =0 then prove that Delta ABC must be isoceles.

If A,B and C are the angles of a triangle and |{:(1,1,1),(1+sinA,1+sinB,1+sinC),(sinA+sin^(2)A,sinB+sin^(2)B,sinC+sin^(2)C):}| =0 then prove that Delta ABC must be isoceles.

If A,B, and C are the angles of a triangle and |(1,1,1),(1+sinA,1+sinB,1+sinC),(sinA+sin^(2)A,sinB+sin^(2)B,sinC+sin^(2)C)|=0, then triangle ABC is a)Isosceles b)Equilateral c)Right - angled d)None of these

If A,B and C are the angles of a triangle and |{:(1,1,1),(1+sinA,1+sinB,1+sinC),(sinA+sin^(2)A,sinB+sin^(2)B,sinCsin^(2)C):}| =0 then Delta ABC must be .

If A, B and C are the angles of a triangle and |(1,1,1),(1+sinA,1+sinB,1+sinC),(sinA+sin^2A,sinB+sin^2B,sinC+sin^2C)|=0 , then the triangle must be :

If in a triangle ABC , (sinA+sinB+sinC)(sinA+sinB-sinC)=3sinAsinB then