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|[H,x,I+x],[I-x,I+x-(z)x]|...

|[H,x,I+x],[I-x,I+x-_(z)x]|

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Matrix A=[{:(0,2y,z),(x,y,-z),(x,-y,z):}] if A A^(T)=I then , (x,y,z)=(...,...,...)(x,y,zgt0)

x_1,x_2, x_3,………., x_n are n observations . sum_(i=1)^(n) (x_i - 2) = 100 " and " sum_(i=1)^(n) (x_i - 5) = 20 then mean barx = …….

If i= (sqrt-1) , prove that following (x+1+i) (x+ 1-i) (x-1-i) (x-1+ i)= x^(4) + 4

In Fig.78, we have (i) ( i i ) (iii)/_M L Y=2/_L M Q , (iv) (v) find ( v i ) (vii)/_L M Q (viii) (ix) (x) ( x i ) (xii)/_X L M=( x i i i ) (xiv)(( x v ) (xvi)2x-10 (xvii))^(( x v i i i )0( x i x ))( x x ) (xxi) (xxii) and ( x x i i i ) (xxiv)/_L M Q=x+( x x v ) (xxvi) 30^(( x x v i i )0( x x v i i i ))( x x i x ) , (xxx) (xxxi) find ( x x x i i ) (xxxiii) xdot( x x x i v ) (xxxv) (xxxvi) ( x x x v i i ) (xxxviii)/_X L M=/_P M L ,\ ( x x x i x ) (xl) find ( x l i ) (xlii)/_A L Y (xliii) (xliv) (xlv) ( x l v i ) (xlvii)/_A L Y=( x l v i i i ) (xlix)(( l ) (li)2x-15 (lii))^(( l i i i )0( l i v ))( l v ) ,\ /_L M Q=( l v i ) (lvii)(( l v i i i ) (lix) x+40 (lx))^(( l x i )0( l x i i ))( l x i i i ) , (lxiv) (lxv) find ( l x v i ) (lxvii) xdot( l x v i i i ) (lxix)

The mean deviation for n observations x_1, x_2, ......... , x_n from their mean X is given by (a) sum_(i=1)^n(x_i- X ) (b) 1/nsum_(i=1)^n(x_i- X ) (c) sum_(i=1)^n(x_i- X )^2 (d) 1/nsum_(i=1)^n(x_i- X )^2

The mean deviation for n observations x_1, x_2, ......... , x_n from their mean X is given by (a) sum_(i=1)^n(x_i- X ) (b) 1/nsum_(i=1)^n|x_i- X | (c) sum_(i=1)^n(x_i- X )^2 (d) 1/nsum_(i=1)^n(x_i- X )^2