A physical quantity `P` is given by `P = (A^(3) B^(1//2))/( C^(-4) D^(3//2))`. Which quantity among `A, B , C, and D` brings in the maximum percentage error in `P`?

A physical quantity P is given by P=(A^(3)B^((1)/(2)))/(C^(-4)D^((3)/(2)) The quantity which brings in the maximum percentage error in P is,(Fractional error in A,B,C and D are equal

A physical quantity P is given by P=(A^(3)B^((1)/(2)))/(C^(-4)D^((3)/(2))) . Due to which physical quantity produced the maximum percentage error in P ?

A physical quantity y is given by y=(P^2Q^(3//2))/(R^4S^(1//2)) The percentage error in A,B , C and D are 1%,2%, 4% and 2% respectively. Find the percentage error in y.

Given Z = (A^4B^(1//3))/(CD^(3//2)) where A, B, C & D are physical quantity. What will be the maximum -percentage error in Z?

Given Z = (A^(4)b^(1//3))/(CD^(3//2)) where A,B,C and D are physical quantity. What will be the maximum percentage error in Z.

P= A^3. B^(1/2) . C^1 . If percentage errors in A, B and C are 1, 2 and 4 respectively, then find the percentage error in P.

If a physical quntity is P = (a^3 b^2)/c and the percentage errors in the measurement of a,b and c are 1%,2% and 3% respectively.Find the maximum percentage error in the measurement of physical quantity P.

A physical quantity X is given by X=(a^(2)b^(2))/(sqrt(c).d) Find the relative error and percentage error in X if percentage errors in a,b,c and d are 1%,3%,4% and 2% respectively.