The velocity-time relation of an electron starting from rest is given by u=id, where `k=2m//s^(2)`. The distance traversed in 3 sec is:-

The velocity-time relation of an electron starting from rest is given by u=kt, where k=2m//s^(2) . The distance traversed in 3 sec is:-

The velocity time relation of an electron starting from rest is given by v=kt where k=2m/s^2 . The distance traversed in 3 second is

the velcoity -time relation of an electron starting from rest is given by v=kt,where h=2 ms^(-2) .calculate the distance traversed in 3s.

The velocity-time relation of an object starting from rest is given by v=3t . When "v" is in "m/s" and "t" in seconds. The distance traversed in "3" seconds is:

An electron starting from rest has a velocity that increases linearly with the time that is v=kt,where k=2 m//sec^(2) .The distance travelled in the first 3 seconds will be

An electron starting from rest has a velocity that increases linearly with the time that is v=kt,where k=2 m//sec^(2) .The distance travelled in the first 6 seconds will be

The initial velocity of a particle is u and the acceleration is given by (kt), where k is a positive constant. The distance travelled in time t is: