(26)(sec8A-1)/(sec4A-1)=

(sec8A-1)/(sec4A-1)=(tan 8A)/(tan2A)

If (sec8A-1)/(sec4A-1)=tanmA.cotnA, then: (m,n)-=....

Prove that (sec8A-1)/(sec4A-1)=(tan8A)/(tan2A)

(sec 8 A-1)/( sec 4A-1)=

Prove that (sec 8A-1)/(sec 4A-1)=(Tan8A)/(Tan2A)

Prove that (sec 8 A-1)/(sec 4A -1)=(tan 8A)/(tan 2A) .

(sec 8 A-1)/( sec 4A-1)= ..................... A) (tan 2A)/( tan 8A) B) (tan 8A)/(tan 2A) C) (cot 8A)/(cot 2A) D) (tan 6A)/(tan 2A)

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

Prove that (sec 8A-1)/( sec 4 A -1) = ( tan 8 A)/( tan 2A).