Mass of a person sitting in a lift is 50 kg . If lift is coming down with a constant acceleration of 10 `m//sec^(2)` . Then the reading of spring balance will be `(g=10m//sec^(2))`

When a man holding spring balance in stationary lift then it's reading is 60 kg . Now if lift starts descends with constant acceleration 1.8 m/ s^(2) then what is the new reading of spring balance in newton (take g =10 m/ s^(2) )

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of 5 m//s^(2) , the reading of the spring balance will be :

A body of mass 1.0 kg is falling with an acceleration of 10 m//s^(2) . Its apparent weight will be (g=10m//sec^(2))

A person of mass 50 kg stands on a weighing scale on a lift . If the lift is descending with a downward acceleration of 9ms^(-2) what would be the reading of the weighing scale? (g =10ms^(-2)) .

A person of mass 50 kg stands on a weighing scale on a lift . If the lift is descending with a downward acceleration of 9ms^(-2) what would be the reading of the weighing scale? (g =10ms^(-2)) .

A person of mass 50 kg stands on a weighing scale on a lift . If the lift is descending with a downward acceleration of 9ms^(-2) what would be the reading of the weighing scale? (g =10ms^(-2)) .

A lift of mass 200 kg is moving upward with an acceleration of 3m//s^(2) . If g=10 m//s^(2) then the tension of string of the lift will be :

In the above problem, if the lift moves up with a constant velocity of 2 m//sec , the reading on the balance will be

A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 ms^(-2) , what would be the reading of the weighing scale ? (g = 10 ms^(-2) )

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49N, when the lift is stationary. If the lift moves downward with an acceleration of 5m//2^2 , the reading of the spring balance will be