[" (27.) If "sin x+cos x=(1)/(5)" ,then "tan2x" is "],[[" (a) "(25)/(17)," (b) "(7)/(25)," (c) "(25)/(7)]]

If sin x+cos x=(1)/(5), then tan 2x is

if sin x+cos x=(1)/(5), then find the value of tan2x.

If 3sin x+4cos x=5, then 6(tan)(x)/(2)-9(sin)^(2)(x)/(2)=

(sin 7x - sin 5x)/(cos 7x + cos 5x) = tan x

If (sin^(4)x)/(2)+(cos^(4)x)/(3)=(1)/(5) then tan^(2)x=(2)/(3)(b)(sin^(8)x)/(8)+(cos^(8)x)/(27)=(1)/(125)tan^(2)x=(1)/(3)(d)(sin^(8)x)/(8)+(cos^(8)x)/(27)=(2)/(125)

(1+sin x+cos x+sin2x+cos2x)/(tan2x)=0

(1 + sin x-cos x) / (1 + sin x + cos x) = tan ((x) / (2))

(1-cos 2x + sin x)/(sin 2x + cos x) = tan x