if a,b,c are in A.P. show that : `| [ x+1, x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c ] |=0`

If a,b,c are in AP show that |[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]|=0

If a,b,c are in AP show that |[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]|=0

if a, b,c are in A.P. then what is the value of: |[x+1,x+2,x+a],[x+2,x+3,x+b],[x+3,x+4,x+c]| ?

If a,b,c are in A.P then the value of det[[x+1,x+2,x+ax+2,x+3,x+bx+3,x+4,x+c]] is

Given a,b,c are in A.P. Then determinant : |(x+1,x+2,x+a),(x+2,x+3,x+b),(x+3,x+4,x+c)| in its simplified form is :

If a,b,c, are in A.P. then |(x+1,x+2,x+a),(x+2,x+3,x+b),(x+3,x+4,x+c)|=

If alpha,beta,gamma are in A.P. then show that , |[x-3,x-4,x-alpha],[x-2,x-3 ,x-beta],[x-1,x-2,x-gamma]|=0

Select and write the correct answer from the given alternatives in each of the following:If a,b,c are in A.P,then |(x+1,x+2,x+a),(x+2,x+3,x+b),(x+3,x+4,x+c)| =

If a,b,c are in A.P., then the determinant |[x+2, x+3, x+2a],[x+3,x+4,x+2b],[x+4,x+5,x+2c]| is

If a, b, c, are in A.P, then the determinant |[x+2,x+3,x+2a], [x+3,x+4,x+2b], [x+4,x+5,x+2c]| is(A) 0 (B) 1 (C) x (D) 2x