`Delta=|(1,(4sinB)/b,cosA),(2a,8sinA,1),(3a,12sinA,cosB)|` is (where `a, b, c` are the sides opposite to angles `A, B, C` respectively in a triangle)

Let (sinA)/(sinB)=(sin(A-C))/(sin(C-B)) , where A , B, C are angles of a triangle ABC. If the lengths of the sides opposite these angles are a,b,c respectively, then

If |(cos(A+B),-sin(A+B),cos2B),(sinA,cosA,sinB),(-cosA,sinA,cosB)|=0 then B =

If |(cos(A+B),-sin(A+B),cos2B),(sinA,cosA, sinB),(-cosA, sinA, cosB)|=0 then the value of B is -

If |(cos(A+B),-sin(A+B),cos2B),(sinA,cosA, sinB),(-cosA, sinA, cosB)|=0 then the value of B is -

Prove that: sin(A+B)+cos(A-B)=(sinA+cosA)(sinB+cosB)

If |{:(cos(A+B),-sin(A+B),cos2B),(sinA,cosA,sinB),(-cosA,sinA,cosB):}|=0 then B =

If sinA=sinB,cosA=cosB , then the value of A in terms of B is

In a triangle ABC, 3sinA + 4cosB = 6 and 4sinB + 3cosA = 1. Find the measure of angle C.

In a triangle ABC, 3sinA + 4cosB = 6 and 4sinB + 3cosA = 1. Find the measure of angle C.

If |[cos(A+B), -sin(A+B), cos2B], [sinA, cosA, sinB], [-cosA, sinA, cosB]|=0 , then B=