Steam at `100^@C` is allowed to pass into a vessel containing 10 g of ice and 100 g of water at `0^@C`, until all the ice is melted and the temperature is raised to `40^@C`. Neglecting water equivalent of the vessel and the loss due to radiation etc. The approximate amount of steam condensed is

Steam at 100^@C is allowed to pass into a vessel containing 10g of ice and 100 g of water at 0^@C until all the ice is melted and the temperature is raised to 50^@C . Neglecting water equivalent of the vessel and the loss due to radiation etc. Calculate how much steam is condensed.

A mass m of steam at 100^(@)C is to passed into a vessel containing 10g of ice and 100g of water at 0^(@)C so that all the ice is melted and the temperature is raised to 5^(@)C neglecting heat absorbed by the vessel, we get

A vessel containing 100 g ice at 0^(@)C is suspended in a room where temperature is 35^(@)C . It was found that the entire ice melted in 10 hour. Now the same vessel containing 100 g of water at 0^(@)C is suspended in the same room. How much time will it take for the temperature of water to rise to 0.5^(@)C . Neglect the heat capacity of the vessel. Specific heat of water and specific latent heat of fusion of ice are 1 cal g^(-1) .^(@)C^(-1) and 80 cal g^(-1) respectively.

100g ice at 0^(@)C is mixed with 100g water at 100^(@)C . The resultant temperature of the mixture is

100g ice at 0^(@)C is mixed with 100g water at 100^(@)C . The resultant temperature of the mixture is

A vessel contains 10^(–1) kg of ice at 0^(@)C . Now steam is passed into the vessel to melt ice. Neglecting the thermal capacity of the vessel, find the mass of water in the vessel when all ice melts into water.

The amount of steam at 100^@ C that should be passed into 600 g of water at 10^@ C to make the final temperature as 40^@ C will be

If 10 g of the ice at 0^@C is mixed with 10g of water at 100^@ C , then the final temperature of the mixture will be