[" IIlustration 24.",1.20" g sample of "Na_(2)CO_(3)" and "K_(2)CO_(3)" was dissolved in water to form "100mL" of a "],[" Solution."20mL" of this solution required "40mL" of "0.1NHCl" for complete neutralization."],[" Calculate the weight of "Na_(2)CO_(3)" in the mixture.If another "20mL" of this solution is treated with "],[" excess of "BaCl_(2)" what will be the weight of the precipitate? "]

1.20 gm sample of NaCO_(3) " and " K_(2)CO_(3) was dissolved in water to form 100 ml of a Solution : 20 ml of this solution required 40 ml of 0.1 N HCl for complete neutralization . Calculate the weight of Na_(2)CO_(3) in the mixture. If another 20 ml of this solution is treated with excess of BaCl_(2) what will be the weight of the precipitate ?

A mixture containing only Na_(2) CO_(3) and K_(2) CO_(3) and weighing 1.22 g was dissolved in water to form 100 mL of solution: 20 mL of this solution required 40 mL of 0.1 N HCl for neutralisation. a. Calculate the weight of K_(2) CO_(3) in the mixture. b. If another 20 mL of the same solution is treated with excess of BaCl_(2) , what will be the weight of precipitate thus obtained? (Molarcular of Na_(2)CO_(3) = 106 , K_(2) CO_(3) = 138, BaCO_(3) = 197.4 )

A mixture containing only Na_(2) CO_(3) and K_(2) CO_(3) and weighing 1.22 g was dissolved in water to form 100 mL of solution: 20 mL of this solution required 40 mL of 0.1 N HCl for neutralisation. a. Calculate the weight of K_(2) CO_(3) in the mixture. b. If another 20 mL of the same solution is treated with excess of BaCl_(2) , what will be the weight of precipitate thus obtained? (Molarcular of Na_(2)CO_(3) = 106 , K_(2) CO_(3) = 138, BaCO_(3) = 197.4 )