`3.6+6.9+9.12+....+3n(3n+3)=`

1,6+2.9+3.12+....+n(3n+3)=

Prove the following by using the principle of mathematical induction for all n in N 3 xx 6 + 6 xx 9 + 9 xx 12 + …..+ (3n)(3n+3) = 3n(n+1)(n+2)

Prove by the principle of mathematical induction, that 3xx6+6xx9+9xx12+....+(3n)xx(3n+3)=3n(n+1)(n+2)

Prove by the principle of mathematical induction, that 3xx6+6xx9+9xx12+....+(3n)xx(3n+3)=3n(n+1)(n+2)

(3) / (6) + (3.5) / (6.9) + (3.5.7) / (6.9 * 12) + ..... prop =

Find the nth term of the series 3.8+6.11+ 9.14+12.17+.. (A) 3n(3n+5) (B) 3n(n+5) (C) n(3n+5) (D) n(n+5)

By method of induction, prove that 1.6 + 2.9 + 3.12 +... +to n terms = n(n +1 )(n+2) for all n in N .

Prove be mathematical induction : (1)/(3.6)+(1)/(6.9)+(1)/(9.12)+...+(1)/(3n(3n+3))=(n)/(9(n+1))

Find the nth term of the series 3.8+6.11+9.14+12.17+...(A)3n(3n+5)(B)3n(n+5) (C) n(3n+5) (D) n(n+5)